Dichloroacetic acid `(CHCI_2COOH)` is oxidised to `CO_(2),H_(2)O` and `CI_(2)` by 600meq of an oxidising agent. Same amount of ammonia to form ammonium dichloroacetate:

Options

A. `0.0167`
B. `0.1`
C. `0.3`
D. `0.6`

Answer

To solve the problem, we need to determine how many moles of ammonia (NH₃) are required to react with the same amount of dichloroacetic acid (CHCl₂COOH) that was oxidized by 600 mL of an oxidizing agent.

### Step-by-Step Solution

1. **Identify the Reaction**:
Dichloroacetic acid (CHCl₂COOH) is oxidized to carbon dioxide (CO₂), water (H₂O), and chlorine (Cl₂). The balanced reaction can be represented as:
\[ \text{CHCl}_2\text{COOH} \rightarrow \text{CO}_2 + \text{H}_2\text{O} + \text{Cl}_2 \]

2. **Determine the Number of Equivalents**:
The problem states that 600 mL of an oxidizing agent is used. To find the number of equivalents, we need to know the concentration of the oxidizing agent. However, since we are given 600 mL, we will consider it as 600 equivalents for the purpose of this calculation.

3. **Calculate Moles of Dichloroacetic Acid**:
Since 600 mL of oxidizing agent corresponds to the oxidation of a certain amount of dichloroacetic acid, we can assume that the same amount of acid will react with ammonia. The equivalent weight of dichloroacetic acid can be calculated based on its molecular weight and the number of moles reacting.

4. **Determine Moles of Ammonia Required**:
The reaction of dichloroacetic acid with ammonia to form ammonium dichloroacetate can be represented as:
\[ \text{CHCl}_2\text{COOH} + \text{NH}_3 \rightarrow \text{NH}_4\text{CHCl}_2\text{COO} \]
Here, one mole of dichloroacetic acid reacts with one mole of ammonia to form one mole of ammonium dichloroacetate.

5. **Final Calculation**:
Since 600 mL of the oxidizing agent corresponds to the oxidation of a certain amount of dichloroacetic acid, the same amount (in equivalents) of ammonia will be needed to react with that amount of acid. Therefore, if 600 mL of oxidizing agent corresponds to 600 equivalents of dichloroacetic acid, it will also require 600 equivalents of ammonia.

### Conclusion:
Thus, the same amount of dichloroacetic acid can be utilized by **600 moles of ammonia** to form ammonium dichloroacetate.