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If valence factor (n-factor) of compound...

If valence factor (n-factor) of compound `NaHC_(2)O_(4).2H_(2)C_(2)O_(4).3K_(2)C_(2)O_(4).4Al_(2)(C_(2)O_(4))_(3).3FeC_(2)O_(4)` in acid base titration is x and redox titration with `KMnO_(4)` is y then value of y/x is:

A

8.4

B

9

C

11.25

D

12

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the n-factor (valence factor) of the compound in two different types of titrations: acid-base titration and redox titration. Let's break down the steps: ### Step 1: Determine the n-factor in Acid-Base Titration (X) 1. **Identify the number of acidic protons (H⁺)** in the compound: - The compound is `NaHC₂O₄.2H₂C₂O₄.3K₂C₂O₄.4Al₂(C₂O₄)₃.3FeC₂O₄`. - Count the number of hydrogen atoms (H): - From `NaHC₂O₄`: 1 H - From `2H₂C₂O₄`: 2 × 2 = 4 H - From `3K₂C₂O₄`: 0 H (no H in K₂C₂O₄) - From `4Al₂(C₂O₄)₃`: 0 H (no H in Al₂(C₂O₄)₃) - From `3FeC₂O₄`: 0 H (no H in FeC₂O₄) - Total H = 1 + 4 = 5 H 2. **Determine the n-factor (X)**: - In acid-base titration, the n-factor is equal to the number of H⁺ ions that can be released. - Therefore, X = 5. ### Step 2: Determine the n-factor in Redox Titration (Y) 1. **Identify the oxidation states of carbon in oxalate (C₂O₄²⁻)**: - In C₂O₄²⁻, the oxidation state of carbon is +3. - When it is oxidized to CO₂, the oxidation state becomes +4. 2. **Calculate the number of electrons transferred per carbon**: - Each carbon transfers 1 electron during the oxidation process. - Count the total number of carbon atoms in the compound: - `2 from NaHC₂O₄` - `2 from 2H₂C₂O₄` (2 × 2 = 4) - `2 from 3K₂C₂O₄` (3 × 2 = 6) - `2 from 4Al₂(C₂O₄)₃` (4 × 3 × 2 = 24) - `2 from 3FeC₂O₄` (3 × 2 = 6) - Total number of carbon atoms = 2 + 4 + 6 + 24 + 6 = 42. 3. **Calculate the total number of electrons transferred by carbon**: - Total electrons from carbon = 42 (1 electron per carbon). 4. **Consider the iron (Fe) contribution**: - Each Fe²⁺ ion is oxidized to Fe³⁺, transferring 1 electron. - There are 3 Fe ions, so total electrons from Fe = 3. 5. **Calculate the total n-factor (Y)**: - Total electrons transferred = 42 (from C) + 3 (from Fe) = 45. - Therefore, Y = 45. ### Step 3: Calculate the ratio y/x 1. **Calculate y/x**: - y/x = Y/X = 45/5 = 9. ### Final Answer The value of y/x is **9**.
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