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In the redox reaction, 2MnO(4)^(-)+5C(2)...

In the redox reaction, `2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O`
20mL of 0.1 M `KMnO_(4)` reacts quantitatively with :

A

20mL of 0.1 M oxalate

B

40mL of 0.1 M oxalate

C

50ml of 0.25 M oxalate

D

50mL of 0.1 M oxalate

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The correct Answer is:
d
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KMnO_(4) reacts with oxalic acid according to the equation: 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to2Mn^(2+)+10CO_(2)+8H_(2)O 20mL of 0.1M KMnO_(4) will react with:

KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

KMnO_(4) react with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O , here 20 ml of 0.1 M KMnO_(4) is equivalemt to

In the redox reaction 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)hArr 2Mn^(2+)+10CO_(2)+8H_(2)O the ion acting as autocatalyst is

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