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In a balanced redox reaction net gain of...

In a balanced redox reaction net gain of electron (s) is equal to net loss of electrons (s).`n_("factor")` is a reaction specific parameter and for intermolecular redox reaction n-factor of oxidising reducing agent is the no. of moles of electron gained /lost by one mole of compound.
Consider the following reaction:
`CrO_(5)+H_(2)SO_(4) to Cr_(2)(SO_(4))_(3)+H_(2)O+O_(2)`
One mole of `CrO_(5)` will liberate how many moles of `O_(2)`?

A

`7/(4)`

B

`5/(4)`

C

1

D

none of these

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a
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In a balanced redox reaction net gain of electron (s) is equal to net loss of electrons (s). n_("factor") is a reaction specific parameter and for intermolecular redox reaction n-factor of oxidising reducing agent is the no. of moles of electron gained /lost by one mole of compound. The n_("factor") of KI in the following reaction is : CuSO_(4)+KI to Cu_(2)I_(2)+K_(2)SO_(4)+I_(2)

In the reaction CrO_(5) + H_(2)SO_(4)rarr Cr_(2)(sO_(4))_(3)+H_(2)O+O_(2) , one mole of CrO_(5) will liberate how many molesof O_(2) :

How many moles of O_(2) will be liberated by one mole of CrO_(5) is the following reaction: CrO_(5) + H_(2) SO_(4) rarr Cr_(2) (SO_(4))_(5) + H_(2)O + O_(2)

Which of the following statements is/are correct about the reaction. 4CrO_(5)+6H_(2)SO_(4)to2Cr_(2)(SO_(4))_(3)+6H_(2)O+7O_(2)

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

Is the reaction BaO_(2)+H_(2)SO_(4)rarrBaSO_(4)+H_(2)O_(2) a redox reaction?

In the following redox reaction Cu(OH)_(2) (s) + N_(2) H_(4)(aq) rarr Cu(s) + N_(2)(g) number of mole of Cu(OH)_(2) reduced by one mol of N_(2) H_(4) is -

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