Calculate volume (in mL) of 3 M KMnO(4) ...

Calculate volume (in mL) of 3 M `KMnO_(4)` in acidified condition required to neutralize 20mL of 2.0 M `H_(2)C_(2)O_(4).2KHC_(2)O_(4).3FeC_(2)O_(4)`

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A mixture of Na_(2)C_(2)O_(4) and KHC_(2)O_(4).H_(2)C_(2)O_(4) required equal volumes of 0.2 M KMnO_(4) and 0.2 M NaOH separately for complete titration the mole ratio of Na_(2)C_(2)O_(4) and KHC_(2)O_(4).H_(2)C_(2)O_(4) in the mixture is

Oxalic acid, H_(2)C_(2)O_(4) , reacts with paramagnet ion according to the balanced equation 5H_(2)C_(2)O_(4)(aq)+2MnO_(4)^(-)hArr2Mn^(2+)(aq)+10CO_(2)(g)+8H_(2)O(l) . The volume in mL of 0.0162 M KMnO_(4) solution required to react with 25.0 mL of 0.022 M H_(2)C_(2)O_(4) solution is :

Oxalic acid, H_(2)C_(2)O_(4) , reacts with paramagnet ion according to the balanced equation 5H_(2)C_(2)O_(4)(aq)+2MnO_(4)^(-)(aq)+6H^(+)(aq)hArr2Mn^(2+)(aq)+10CO_(2)(g)+8H_(2)O(l) . The volume in mL of 0.0162 M KMnO_(4) solution required to react with 25.0 mL of 0.022 M H_(2)C_(2)O_(4) solution is

Calculate the moles of KMnO_(4) required to react completely with 2 m and 1500 mL of K_(2)C_(2)O_(4)H_(2)C_(2)O_(4) in acidic medium.

'a' gm KHC_(2)O_(4) is used to neutralize 100 mL of 0.02 M KMnO_(4) in acid medium, where as 'b' gm KHC_(2)O_(4) is used to neutralize 100 mL of 0.02 M Ca(OH)_(2) then,

Volume of 0.1M KMnO_(4) solution required to oxidise 20ml of 0.5M of H_(2)O_(2) solution in presence of H_(2)SO_(4) is? (A) 80ml, (B)40ml (C)20ml (D) 10ml

A mixture of H_(2)C_(2)O_(4) and NaHC_(2)O_(4) weighing 2.02 g was dissolved in water and the solution made uptp one litre. 10 mL of this solution required 3.0 mL of 0.1 N NaOH solution for complete neutralization. In another experiment 10 mL of same solution in hot dilute H_(2)SO_(4) medium required 4 mL of 0.1N KMnO_(4) KMnO_(4) for compltete neutralization. Calculate the amount of H_(2)C_(2)O_(4) and NaHC_(2)O_(4) in mixture.

20ml of "0.5 M KMnO"_(4) in acidic media exactly neutralises 30ml of a H_(2)O_(2) solution. The volume strength of H_(2)O_(2) solution will be?

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