Let `f(0)=sqrt(sin^4theta+4cos^2theta)-sqrt((cos^4theta)+4sin^2theta)` , then

(sin^4theta-cos^4theta)/(sin^2theta-cos^2theta) = ………………..

2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to

sin^2theta+cos^4theta=cos^2theta+sin^4theta

Prove that sin^4theta-cos^4theta=sin^2theta-cos^2theta .

The value of (2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta))/(cos^(4)theta-sin^(4)theta-2cos^(2)theta) is :

The value of (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) is (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) का मान है:

The value of cos^4theta+sin^4theta-6cos^2theta is (a) cos2theta (b) sin2theta (c) cos4theta (d) none of these

The range of the function f(theta)=sqrt(8sin^(2)theta+4cos^(2)theta-8sin theta cos theta) is