If x and y are connected parametrically by the equations given, without eliminating the parameter, Find `(dy)/(dx)`.
`x=a(theta-sintheta), y=a(1+costheta)`

Explanation

given `x=a(θ−sinθ),y=a(1+cosθ)`

`⇒ dx/(dθ)=a(1−cosθ)`

`=>dx/(dθ) =a[0+(−sinθ)]=−asinθ`

`dy/dx=−(asinθ)/
(a(1−cosθ))`

`= −(2sin (θ/2)cos (θ/2))/
(2sin^2(θ/2))`

`= −cos (θ/2)/
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