A simple wave motion represented by `y=5(sin 4pi t+sqrt3 cos 4pit)`. Its amplitude is

A simple harmonic motion is represented by : y=5(sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

A simple harmonic motion is represented by : y = 5(sin 3pi t + sqrt(3) cos 3pi t)cm The amplitude and time period of the motion are :

A simple harmonic motion is represented by : y=59sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

A simple harmonic motion is given by y = 5(sin3pit + sqrt(3) cos3pit) . What is the amplitude of motion if y is in m ?

A simple harmonic motion is represented by y = 8 sin 10 pi t + 6 cos 10 pit , where is in cm and t is in sec. Calculate the amplitude time period and intial phase.

Two simple harmonic motions are represented by y_(1)=5[sin2pit+sqrt(3)cos2pit] and y_(2)=5sin(2pit+(pi)/(4)) The ratio of their amplitudes is