A magnetic field strength `(H) 3xx10^(3) Am^(-1)` produces a magnetic field of induction `(B)` of `12piT` in an iron rod. Find the relative permeability of iron ?

A magnetic field strength (H) 3 xx 10^3 Am^-1 produces a magnetic field of induction (B) of 12 pi T in an iron rod . The relative permeability of iron is

A magnetising field of 2xx10^(3)Am^(-1) produces a magnetic flux density of 8piT in an iron rod. The relative permeability of the rod will be

A magnetising field of 2xx10^(3)Am^(-1) produces a magnetic flux density of 8piT in an iron rod. The relative permeability of the rod will be

A magnetizing field of 5000 A/m produces a magnetic flux of 5 xx 10^(-5) Wb in an iron rod of 0.5 cm^(2) area of cross-section. The permeability of the rod is (in Wb A^(-1) m^(-1) )

A magneting field of 1600 Am^(-1) produces a magnetic flux of 2.4xx10^(-5) wb in an iron bar of cross-sectional area 0.2cm^(2) .Calculate the permeability and susceptibility of the bar.