The amplitide of a particle due to superposition of following S.H.Ms. Along the same line is
`{:(X_(1)=2 sin 50 pi t,,X_(2)=10 sin(50 pi t +37^(@))),(X_(3)=-4 sin 50 pi t,,X_(4)=-12 cos 50 pi t):}`

The amplitude of a particle due to superpositon of following S.H.Ms. . Along the same line is X_(1) = 2 sin 50 pi t , X_(2) = 10 sin (50pi t + 37^(@)) X_(3) = -4 sin 50 pi t , X_(4) = -12 cos 50 pi t

The amplitude of the vibrating particle due to superposition of two SHMs , y_(1)=sin (omega t+(pi)/(3)) and y_(2)=sin omega t is :

In case of superposition of waves (at x = 0). y_1 = 4 sin(1026 pi t) and y_2 = 2 sin(1014 pi t)

A particle moves along y - axis according to the equation y("in cm") = 3 sin 100pi t + 8sin^(2) 50pi t - 6

A particle moves along y - axis according to the equation y("in cm") = 3 sin 100pi t + 8sin^(2) 50pi t - 6

On the superposition of two waves [y_1 = 3 sin (50 pi t - 20x)] and [y_2 = 3sin (50pi t -20 x +(pi/3)] the equation resultant wave will be

On the superposition of two waves [y_1 = 3 sin (50 pi t - 20x)] and [y_2 = 3sin (50pi t -20 x +(pi/3)] the equation resultant wave will be

The instantaneous potential difference between points. A. 8 sin (50 pi t+37 (pi)/180) B. 8 sin(50 pit-37(pi)/180) C. 10 sin(50pit) D. 10 cos(50 pit)

The equations of two SH M's are X_(1) = 4 sin (omega t + pi//2) . X_(2) = 3 sin(omega t + pi)