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Tangent to the curve y=x^2+6 at a point ...

Tangent to the curve `y=x^2+6` at a point `(1,7)` touches the circle `x^2+y^2+16x+12y+c=0 `at a point `Q`, then the coordinates of `Q` are (A) `(-6,-11)` (B) `(-9,-13)` (C) `(-10,-15)` (D) `(-6,-7)`

Text Solution

Verified by Experts

`y=x^2+6`
differentiate withh respect to x
`y'=2x=2`
`y-7=2(x-1)`
`y-2x-5=0`
`T:y-2x-5=0`
`y+6=-1/2(x+8)`
`2y+x+20=0-(1)`
...
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