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A physical parameter a can be determined...

A physical parameter `a` can be determined by measuring the parameters `b, c, d, and e` using the relation `a=b^(alpha)c^(beta)//d^(gamma)e^(delta)`. If the maximum errors in the measurement of `b, c , d, and e are b_(1) %,c_(1)% ,d_(1)% , and e_(1) %`, then the maximum error in the value of `a` determined by the experminent.

A

`(b_(1)+c_(1)+d_(1)+e_(1))%`

B

`(b_(1)+c_(1)-d_(1)-e_(1))%`

C

`(alpha b_(1)+beta c_(1)-gammad_(1)-deltae_(1))%`

D

`(alphab_(1)+betac_(1)+gammad_(1)+deltae_(1))%`

Text Solution

Verified by Experts

The correct Answer is:
D
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