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An electric bulb is designed to draw P(...

An electric bulb is designed to draw `P_(0)` power at `V_(0)` voltage. If the voltage is `V`, it drawas power. Then

A

`P=((V_(0))/(V))^(2)P_(0)`

B

`P=((V)/(V_(0)))^(2)P_(0)`

C

`P=((V)/(V_(0)))P_(0)`

D

`P=((V_(0))/(V))P_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
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