A particle takes a time `t_(1)` to move down a straight tunnel from the surface of earth to its centre. If gravity were to remain constant this time would be `t_(2)` calculate the ratio `(t_(1))/(t_(2))`

A train accelerates from at the constant rate b for time t_(2) at a constant rate a and then it retards at the comes to rest. Find the ratio t_(1) // t_(2) .

A particle move with velocity v_(1) for time t_(1) and v_(2) for time t_(2) along a straight line. The magntidue of its average acceleration is

A particle move with velocity v_(1) for time t_(1) and v_(2) for time t_(2) along a straight line. The magntidue of its average acceleration is

A simple pendulum has a time period T_(1) on the surface of earth of radius R. When taken to a height of R above the earth's surface, its time period is T_(2) , ratio (T_(2))/(T) is

A train accelerates from rest at a constant rate a for time t_(1) and then it retards at the constant rate b for time t_(2) then comes to rest. Find the ratio t_(1) / t_(2) .

The time period of a simple pendulum is T_(1) on the surface of earth. If taken to a height 2 R above the surface of earth, the time period becomes T_(2) . What will be the value of T_(1)//T_(2) ? (R is the radius of earth).

A ring takes time t_(1) in slipping down an inclined plane of length L, whereas it takes time t_(2) in rolling down the same plane. The ratio of t_(1) and t_(2) is -

A ring takes time t_(1) in slipping down an inclined plane of length L, whereas it takes time t_(2) in rolling down the same plane. The ratio of t_(1) and t_(2) is -