In the given figure, AD = AE and AD^2 = ...

In the given figure, AD = AE and `AD^2 = BD xx EC` prove that: triangles ABD and CAE are similar.

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AD=AE
`/_ADE=/_AED`
`/_ADB=/_AEC`
`AD^2=BD*EC`
`(AD)/(BD)=(EC)/(AD)`
`(AD)/(BD)=(EC)/(AE)`
`In/_ABD and /_CAE`
`(AD)/(BD)=(EC)/(AE)`
...

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