A uniiform disc of radius `r` spins with angular velocity `omega` and angular acceleration `alpha`. If the centre of mass of the disc has linear acceleration `a`, find the magnitude and direction of aceeleration of the point `1,2`, and `3`.

If angular velocity of a disc depends an angle rotated theta as omega=theta^(2)+2theta , then its angular acceleration alpha is :

If a disc of mass m and radius R totates with an angular acceleration a, of the torque acting on the disc is

A uniform disc of radius R = 2 sqrt3 m is moving on a horizontal surface without slipping. At some instant its angular velocity is omega = 1 rad/s and angular acceleration is a alpha = sqrt3 "rad"//s^(2) . (a) Find acceleration of the top point A. (b) Find acceleration of contact point B. (c) Find co - oridnates (r , theta) for a point P which has zero acceleration

A uniform disc of radius R is spinned to the angular velocity omega and then carefully placed on a horizontal surface. How long will the disc be rotating on the surface if the friction coeffiecient is equal to k? The pressure exerted by the disc on the surface can be neglected as uniform.

A uniform disc of radius R is spinned to the angular velocity omega and then carefully placed on a horizontal surface. How long will the disc be rotating on the surface if the friction coeffiecient is equal to k ? The pressure exerted by the disc on the surface can be regarded as uniform.

If angular velocity of a disc depends an angle rotated theta as omega=theta^(2)+2theta , then its angular acceleration alpha at theta=1 rad is :

If angular velocity of a disc depends an angle rotated theta as omega=theta^(2)+2theta , then its angular acceleration alpha at theta=1 rad is :

If angular velocity of a disc depends an angle rotated theta as omega=theta^(2)+2theta , then its angular acceleration alpha at theta=1 rad is :