When a lens of power `P` (in air) made of material of refractive index `mu` is immersed in liquid of refractive index `mu_(0)` Then the power of lens is:

A concave lens made of a material of refractive index mu_g is immersed in a medium of refractive index mu_l , equal to and

A double convex lens of refractive index m_(1) is immersed in a liquid of refractive index m_(2) . This lens will act as:

A double convex lens of refractive index m_(1) is immersed in a liquid of refractive index m_(2) . This lens will act as:

What happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3?

A converging lens has a focal length of 20 cm in air. It is made of a material of refractive index 1.6. If it is immersed in a liquid of refractive index 1.3, what will be the new focal length? How does the nature of the lens change. If this lens is immersed is a liquid of refractive index 1.8 ?

Explain what happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3 .

Explain what happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3 .