The mass of the liquid flowing per second per unit area of cross section of the tube is proportional to `P^(x) and v^(y)` , where `P` is the pressure difference and `v` is the velocity , then the relation between x and Y is

The mass of the liquid flowing per second per unit area of cross-section of the tube is proportional to (pressure difference across the ends)^(n) and (average velocity of the liquid)^(m). Which of the following relations between m and n is correct?

The mass of the liquid flowing per second per unit area of cross-section of the tube is proportional to (pressure difference across the ends)^(n) and (average velocity of the liquid)^(m) . Which of the following relations between m and n is correct?

How does the pressure of liquid depend on the area 'of cross section of tube of flow?

V is the volume of a liquid flowing per second through a capillary tube of length l and radius r, under a pressure difference (p). If the velocity (v), mass (M) and time (T) are taken as the fundamental quantities, then the dimensional formula for eta in the relation V=(pipr^(4))/(8etal)

For the equation P prop m^(x).v^(y) where P is momentum, m is mass and v velocity. Then the value of x and y are

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section A_(1) and A_(2) are v_(1) and v_(2) respectively. The difference in the levels of the liquid in the two vertical tubes is h . Then