[2y(1-sin theta+cos theta)^(2)=2(1+cos theta)(1-sin theta)],[quad 1+cos theta-sin^(2)theta]

Prove that (1-sin theta+cos theta)^(2)=2(1+cos theta)(1-sin theta)

((sin theta+cos theta)^(2)-1)/(sin theta*cos theta)

Prove that: (1-sin theta + cos theta)^(2) = 2(1+ cos theta) (1-sin theta) .

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

(sin theta-cos theta+1)/(sin theta+cos theta-1)=(1+sin theta)/(cos theta)

Prove that (sin theta+cos theta)/(sin theta- cos theta) + (sin theta - cos theta)/(sin theta + cos theta) = ( 2sec^(2) theta)/(tan^(2) theta -1) .

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

Prove (cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)

(cos theta)/(1-sin theta)=(1+cos theta+sin theta)/(1+cos theta-sin theta)