[" 69."int_(0)^(3)sqrt((x^(3))/(3-x))dx=],[" 1) "(17 pi)/(8)quad " 2) "(27 pi)/(8)]

int_(0)^(pi//2)(1)/(1+tan^(3)x)dx=

Show that : int_(1)^(2)sqrt((x-1)(2-x))dx=(pi)/(8) .

int_(0)^( pi/8)(1)/(1+4x^(2))dx=?

int_(0)^( pi/6)(sqrt(3cos2x-1))/(cos x)dx

int_(0)^(pi//6)(2+3x^(2))cos3x dx= (a) 1/36(pi+16)

The integral int_(0)^( pi)sqrt(1+4sin^(2)((x)/(2))-4sin((x)/(2))dx) equal (1)pi-4(2)(2 pi)/(3)-4-4sqrt(3)(3)4sqrt(3)-4(4)4sqrt(3)-4-(pi)/(3)

int_(pi//8)^(3pi//8)(1)/(1+cotx)dx=

int_(0)^(tan((3 pi)/(8))){x}dx equals

int_(sqrt(3))^(sqrt(8))xsqrt(1+x^(2))dx=?

int_(0)^(pi) cos^(8) x dx=