In the given figure, O is the centre of ...

In the given figure, O is the centre of the circle and BA = AC. If `angleABC=50^@`, find `angleBOC` and `angleBDC.`

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BA=AC
`/_ABC=/_ACB`
`50^@=/_ACB`
`In/_ABC`
`/_A+/_B+/_C=180^@`
`/_A+50+50=180`
`/_A=80^@`
`/_BOC=2/_A`
...

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