An electron has a mass of `9.1 xx 10^(-31)kg`. It revolves round the nucleus in a circular orbit of radius `0.529 xx 10^(-10)` metre at a speed of `2.2 xx 10^(6) m//s`. The magnitude of its linear momentum in this motion is
The electron in a hydrogen atom moves in circular orbit of radius 5xx10^(-11)m with a speed of 0.6pixx10^(6)m//s then
Mass of an electron is 9.0xx10^(-31) kg . It revolves around the nucleus of an atom in a circular orbit of radius 4.0 Å with a speed of 6.0 xx10^(6) ms^(-1) . Calculate the angular momentum of the electron.
An electron revolves around the nucleus of an atom in a circular orbit of radius 4 Å with a speed of 5xx 10^(6)m//s . What is the angular momentum of the electron ? [ m_(e) = 9 xx 10^(-31) kg ].
An electron in an atom is revolving round the nucleus in a circular orbit of radius 5.3xx10^(-11) m, with a speed of 2xx10^(6)ms^(-1) . Find resultant orbital magnetic moment and angular momentum of electron. (e = 1.6 xx 10^(-19) C , m = 9.1 xx 10 kg )
If an electron is revolving in a circular orbit of radius 0.5A^(@) with a velocity of 2.2xx10^(6)m//s . The magnetic dipole moment of the revolving electron is
An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-
An electron revolves around the nucleus of an atom in a circular orbit of radius 4 Å with a speed of 6.0 xx 10^(6) m//s . If mass of electron is 9.0 xx 10^(-31) kg , what is its angular momentum ?
