An electron jumps from the `4th` orbit to the `2nd` orbit of hydrogen atom. Given the Rydberg's constant `R = 10^(5) cm^(-1)`. The frequency in `Hz` of the emitted radiation will be
An electron jumps from the 4th orbit to the 1st orbit of hydrogen atom. Given the Rydberg's constant R=10^(5) cm^(-1) . The frequency in Hz of the emitted radiation will be
An electron jumps from the fourth orbit to the second orbit hydrogen atom. Given the Rydberg's constant R = 10^(7) cm^(-1) . The frequecny , in Hz , of the emitted radiation will be
A sample of hydrogen gas in its ground state is irrdation with photon of 10.2eV energies The radiation from the above the sample is used to irradiate two other the sample of excited ionized He^(+) and excited ionized Li^(2+) , respectively . Both the ionized sample absorb the incident radiation. An electron jumps from the 4^(th) orbit to 2^(nd) orbit of hydrogen atom . .Given the Rydberg's constant r=10^(5)cm^(-1) , the frequency in hertz of the emitted radiation will be
An electron jumps from 5th orbit to 4th orbit of hydrogen atom. Taking the Rydberg constant as 10^(7) per meter. What will be the frequency of radiation emitted ?
An electron jumps from 3rd to 2nd orbit of hydrogen atom. Taking the Rydberg constant as 10^(7) m^(-1) , what will be the frequency of the radiation emitted?
If an electron drops from 4th orbit to 2nd orbit in an H-atom, then
If an electron drop from 4th orbit to 2nd orbit in an H-atom, then
When an electron jumps from higher orbit to the second orbit in hydrogen, the radiation emitted out will be in (R=1.09xx10^(7)m^(-1))
An electron jumps from the 3rd orbit to the ground orbit in the hydrogen atom. If R_H= 10^7 /m then the frequency of the radiation emitted in the transition is
The wavelength of radiation emitted is lambda_(0) when an electron jumps from the third to the second orbit of hydrogen atom. For the electron jump from the fourth to the second orbit of hydrogen atom, the wavelength of radiation emitted will be
