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If m is mass of electron, v its velocity...

If `m` is mass of electron, `v` its velocity, `r` the radius of stationary circular orbit around a nucleus with charge `Z_(e)`, then from Bohr's first postulate, the kinetic energy `k = (1)/(2)mv^(2)` of the electron in `C.G.S.` system is equal to

A

`(1)/(2) (Ze^(2))/(r)`

B

`(1)/(2) (Ze^(2))/(r^(2))`

C

`(Ze^(2))/(r)`

D

`(Ze)/(r^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
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