An electron makes a transition from orbit `n = 4` to the orbit `n = 2` of a hydrogen atom. The wave number of the emitted radiations `(R =` Rydberg's constant) will be
An electron changes its position from orbit n = 4 to the orbit n = 2 of an atom. The wavelength of the emitted radiation's is (R = Rydberg's constant)
An electron makes transition form n=3 , n=1 state in a hydrogen atom. The maximum possible number of photons emitted will be
When an electron jumps from n=4 to n=2 orbit in a hydrogen atom, we get,
If the electron in the hydrogen atom jumps from third orbit to second orbit the wavelength of the emitted radiation in term of Rydberg constant is
The transition of an electron from a 4s orbital to ls orbital in hydrogen atom causes
An electron transits for n^(th) orbit to ground in a hydrogen-like atom (Z = 11). The wavelength of emitted radiation, lambda is equal to the de Broglie wavelength of electron in n^(th) orbit. Choose the correct options.
The frequency of revolution of an electron in nth orbit is f_(n) . If the electron makes a transition from nth orbit to (n = 1) th orbit , then the relation between the frequency (v) of emitted photon and f_(n) will be
In hydrogen atom, electron makes transition from n = 4 to n = 1 level. Recoil momentum of the H atom will be
