The wavelength of the first line of Balmer series is 6563 Å . The Rydberg's constant is
The wavelength of first line of Balmer series is 6563Å . The wavelength of first line of Lyman series will be
The wavelength of the third line of the Balmer series for a hydrogen atom is -
The wavelength of H_alpha line in the Balmer series is 6563 Å . Compute the value of Rydberg constant and hence obtain the wavelength of H_beta line of Balmer series.
If the wavelength of the first line of the Balmer series of hydrogen is 6561 Å , the wavelngth of the second line of the series should be
The wavelength of the first line of Balmer series in hydrogen atom is 6562.8Å . Calculate ionisation potential of hydrogen and also, the wavelength of first line of Lyman series.
The wavelength of the first line of the Balmer series of hydrogen atom is lamda . The wavelength of the corresponding line line of doubly ionized lithium atom is
