The third line of Balmer series of an ion equivalent to hydrogen atom has wavelength of 108.5mm . The ground state energy of an electron of this ion will e
If the shortest wavelength of Lyman series of hydrogen atom is x, then the wavelength of first member of Balmer series of hydrogen atom will be
The first member of the Balmer series of hydrogen atom has wavelength of 6563 A. Calculate the wavelength and frequency of the second member of the same series.
The shortest wavelength of Lyman series of the hydrogen atom is equal to the shortest wavelength of Balmer series of a hydrogen -like atom of atomic number Z. The value of Z is equal to
the wavelength of the first line of lyman series for hydrogen atom is equal to that of the second line of balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is
A double charged lithium atom is equivalent to hydrogen whose atomic numer is 3 . The wavelength of required radiation for emitted electron from first to third Bohr orbit in Li^(++ will be (lonisation energy of hydrogen atom is 13.6 eV )
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion.The atomic number Z of hydrogen like ion is (a) 3 (b) 4 (c) 1 (d) 2
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen-like ion. The atomic number Z of hydrogen-like ion is
