Excitions energy of hydrogen atom is 13.6 eV mathc the following
If the ionization energy for the hydrogen atom is 13.6 eV , the energy required to excite it from the ground state to the next higher state is nearly
The energy of a photon of wavelength 4000 Å is (use h=6.66xx10^(-34) J-s)
The ionization potential of a hydrogen atom is 13.6 eV. What will be the energy of the atom corresponding to n=2?
The ionization energy of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by electromagnetic radiation of energy 12.1 eV. How many spectral lines will be emitted by the hydrogen atoms
The ionization energy of a hydrogen atom is 13.6eV. The energy of the third-lowest electronic level in doubly ionized lithium (Z = 3) is -
If the ionization potential of hydrogen atom is 13.6eV , the energy required to remove from the third orbit of hydrogen atom is k//2eV . Find the value of k …….
