Home
Class 12
PHYSICS
For electron moving in n^(th) orbit of t...

For electron moving in `n^(th)` orbit of the atom , the angular velocity is proportional to:

A

n

B

`1//n`

C

`n`

D

`1//n`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ATOMIC AND NUCLEAR PHYSICS

    ERRORLESS |Exercise Ordinary|15 Videos
  • ATOMIC AND NUCLEAR PHYSICS

    ERRORLESS |Exercise Nuckeus, Nuclear Reaction|2 Videos
  • ALTERNATING CURRENT

    ERRORLESS |Exercise SET|15 Videos
  • COMMUNICATION SYSTEM

    ERRORLESS |Exercise S E T|14 Videos

Similar Questions

Explore conceptually related problems

For an electron moving in n^(th) orbit of H-atom the angular velocity is proportional to

If an electron is moving in nth orbit of H-atom, then its velocity is-

In Bohr's orbit , kinetic energy of an electron in the n^(th) orbit of an atom in terms of angular momentum is propotional to

If an electron is moving in the n^(th) orbit of the hydrogen atom, then its velocity (v_(n)) for the n^(th) orbit is given as :

The angular speed of the electron in the n^(th) Bohr orbit of the hydrogen atom is proportional to

The magnetic field induction produced at the centre of orbit due to an electron revolving in n^(th) orbit of hydrogen atom is proportional to

de-Broglie wavelength associated with an electron revolving in the n^(th) state of hydrogen atom is directily proportional to

Assertion: The de Broglie wavelength of an electron in n^(th) Bohr orbit of hydrogen is inversely proportional to the square of quantum number n. Reason: The magnitude of angular momentum of an electron in n^(th) Bohr orbit of hydrogen atom is directly proportional to n.

An electron moves in Bohr's orbit. The magnetic field at the centre is proportional to

Single electron is orbiting in n^(th) orbit of hydrogen atom. The magnetic field prodruced by the electron at the nucleus will be proportional to n^(-k) . Find the value of k.