When an electron in hydrogen atom is excited, from its `4`th to `5`the stationary orbit, the change in angular momentum of electron is (Planck's constant: `h = 6.6 xx 10^(-34) J-s`)
When an electron in hydrogen atom is excited,from its 4th to 5th stationary orbit,the change in angular momentum of electron is (Planck's constant: ,[h=6.6times10^(-34J-s)]
Give the order of the following : Planck's constant ( 6.63xx10^(-34) J-s)
When an electron in hydrogen atom revolves in stationary orbit, it
If energy of the electron in hydrogen atom in some excited state is -3.4e V then what will be its angular momentum
The orbital angular momentum of electron in 4s orbital of H atom is ……….
The energy of an electron in excited hydrogen atom is -3.4 eV . Then, according to Bohr's therory, the angular momentum of the electron of the electron is
The energy of hydrogen atom in excited state is -3.4 eV. The angular momentum of electron is
The minimum orbital angular momentum of the electron in a hydrogen atom is
Find the value of angular momentum of an electron in the 4^(th) orbit of an atom.
The energy of an electron in an excited hydrogen atom is - 3.4 e V . Calculate the angular momentum . Given : Rydbrg's R = 1.09737 xx 10^(-7) m^(-1) . Plank's constant h = 6.626176 xx 10^(-34) J - s , speed of light c = 3 xx 10^(8) m s^(-1).
