The wave number of the first line in the balmer series of Be^(3+) ?
The wave number of the series limit of Lyman series is -
In terms of Rydberg's constant R , the wave number of the first Balman line is
The wave number of the first line in the Balmer series of hydrogen is 15200 cm^(-1) . What would be the wavenumber of the first line in the Lyman series of the Be^(3+) ion?
Given the value of Rydberg constant is 10^(7)m^(-1) , the waves number of the lest line of the Balmer series in hydrogen spectrum will be:
Using the Rydberg formula, calculate the wavelength of the first four spectral lines in the Lyman series of the hydrogen spectrum.
According to the Rydberg formula, the wavelengths of the first two spectral line in the Lyman series of the hydrogen spectrum, are
The transiton in He^(+) ion that will have the same wave number as the first line of lyman series of hydrogen will be
