The second member of Lyman's series is hydrogen spectrum has a wavelength of 5400 Å. Calculate the wavelength of the first member.
The first line of the lyman series in a hydrogen spectrum has a wavelength of 1210 Å. The corresponding line of a hydrogen like atom of Z=11 is equal to
For the first member of Balmer series of hydrogen spectrum, the wavelength is lamda . What is the wavelength of the second member?
If the wavelength of the first member of Balmer series in hydrogen spectrum is 6563 Å, calculate the wavelength of the first member of Lymen series in the same spectrum.
The shortest wavelength in Lyman series is 912 Å. The shortest wavalength in Paschen series is
If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be
The Wavelength of first member of Balmer series in hydrogen spectrum is lambda . Calculate the wavelength of first member of Lymen series in the same spectrum
