The energy of an excited hydrogen atom is -0.85 eV . Find the angular momentum of the electron. (h = 6.63 xx 10^(-34) J.s., pi = 3.142, E_(1) = -13.6 eV)
The energy of an electron in an excited hydrogen atom is - 3.4 e V . Calculate the angular momentum . Given : Rydbrg's R = 1.09737 xx 10^(-7) m^(-1) . Plank's constant h = 6.626176 xx 10^(-34) J - s , speed of light c = 3 xx 10^(8) m s^(-1).
The energy of electron in an excited hydrogen atom is -3.4eV . Its angular momentum according to bohr's theory will be
The energy of an excited hydrogen atom is 0.38 eV. Its angular momentum is n . h/(2pi) . Find n
The energy of an excited H-atom is -3.4eV . Calculate angular momentum of e^(-)
The energy of an electron in excited hydrogen atom is -3.4 eV . Then, according to Bohr's therory, the angular momentum of the electron of the electron is
The energy of hydrogen atom in excited state is -3.4 eV. The angular momentum of electron is
The energy of electron in first excited state of H -atom is -3.4 eV its kinetic energy is
