An electron changes its position from orbit `n = 4` to the orbit `n = 2` of an atom. The wavelength of the emitted radiation's is `(R =` Rydberg's constant)
An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be
In Lyman series the wavelength lambda of emitted radiation is given by (R is rydberg constant)
if the electron in hydrogen orbit jumps form third orbit to second orbit, the wavelength of the emitted radiation is given by
If the electron in the hydrogen atom jumps from third orbit to second orbit the wavelength of the emitted radiation in term of Rydberg constant is
When an electron jumps from the orbit n=2 to n=4, then wavelength of the radiations absorbed will be where, (where R is Rydberg's constant)
When the electron in a hydrogen atom jumps from the second orbit to the first orbit , the wavelength of the radiation emitted is lamda . When the electron jumps from the third orbit to the first orbit , of the same atom , the wavelength of the emitted radiation would be
An electron transits for n^(th) orbit to ground in a hydrogen-like atom (Z = 11). The wavelength of emitted radiation, lambda is equal to the de Broglie wavelength of electron in n^(th) orbit. Choose the correct options.
If, an electron in hydrogen atom jumps from an orbit of lelvel n=3 to an orbit of level n=2, emitted radiation has a freqwuency (R= Rydbertg's contant ,c = velocity of light)
