When a sample of solid lithium is placed in a flask of hydrogen gas then following reaction happened `._1^1 H + ._3 Li^7 rarr ._2 He^4 + ._2He^4`. This statement is. .
In the following reaction the value of 'X' is. ._7 N^14 + ._2 He^4 rarr X + ._1 H^1 .
Calculate the energy released in the following reaction ._3Li^6 + ._0n^1 to ._2He^4 + ._1H^3
The reaction ._(1)D^(2) + ._(1)T^(3) rarr ._(1)He^(2) + ._(0)n^(1) is an example of
The bombardment of Lithium with protons gives rise to the following reaction: ._3Li^7+._1H^1 to .2_He^4+.2_He^4+Q The atomic masses of lithium, hydrogen and helium are : 7.016u, 1.008u and 4.004u resp. Find the initial energy of each of alpha particle. Take 1a.m.u=931MeV .
Calculate the energy released in joules and MeV in the following nuclear reaction: ._(1)H^(2) + ._(1)H^(2) rarr ._(2)He^(3) + ._(0)n^(1) Assume that the masses of ._(1)H^(2) , ._(2)He^(3) , and neutron (n) , respectively, are 2.40, 3.0160, and 1.0087 in amu.
Which is the missing particle in the following nuclear reaction ? ""_(3)Li^(7) + ""_(1)H^(2) rarr ""_(3)Li^(8) + ?
Calculate the loss in mass during the change: ._(3)Li^(7) + ._(1)He^(1) rarr 2 ._(2)He^(4) + 17.25 MeV
In the nuclear raction given by ._2He^4 +._7N^(14) rarr ._1H^1 +X the nucleus X is
The equation: 4._(1)^(1) H^(+) rarr ._(2)^(4) He^(2+) + 2e + 26MeV represnets.
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