A man sets his watch by a whistle that is 2 km away. How much will his watch be in error. (speed of sound in air 330 m / sec )

Options

A. 3 seconds fast
B. 3 seconds slow
C. 6 seconds fast
D. 6 seconds slow

Answer

To solve the problem, we need to determine how much time it takes for the sound from the whistle to reach the man who is 2 km away. We can then use this time to find out how much the man's watch will be in error when he sets it based on the sound of the whistle.

### Step-by-Step Solution:

1. **Identify the given data:**
- Distance to the whistle = 2 km = 2000 meters
- Speed of sound in air = 330 m/s

2. **Calculate the time taken for the sound to travel to the man:**
- We can use the formula:
\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
- Plugging in the values:
\[ \text{Time} = \frac{2000 \text{ meters}}{330 \text{ m/s}} \]

3. **Perform the calculation:**
- Dividing 2000 by 330:
\[ \text{Time} \approx 6.06 \text{ seconds} \]
- For practical purposes, we can round this to approximately 6 seconds.

4. **Determine the error in the watch:**
- The man hears the whistle 6 seconds after it actually blows. Therefore, when he sets his watch to the time of the whistle, his watch will be 6 seconds slow.

5. **Conclusion:**
- The watch will be in error by approximately 6 seconds slow.

### Final Answer:
The man's watch will be 6 seconds slow.

---