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When two sound waves with a phase differ...

When two sound waves with a phase difference of ` pi //2`, and each having amplitude A and frequency `omega` , are superimposed on each other, then the maximum amplitude and frequency of resultant wave is

A

`(A)/(sqrt(2)) : (omega)/(2)`

B

`(A)/(sqrt(2)) : omega`

C

`sqrt(2) A : (omega)/(2)`

D

`sqrt(2)A : omega`

Text Solution

Verified by Experts

The correct Answer is:
D
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