Home
Class 11
PHYSICS
The minimum intensity of sound is zero a...

The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencie4s when

A

Two sources are vibrating in opposite phase

B

The amplitude of two sources are equal

C

At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line

D

Both the sources are in the same phase

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • WAVES AND SOUND

    ERRORLESS |Exercise Beats|51 Videos

  • WAVES AND SOUND

    ERRORLESS |Exercise Stationary Waves|39 Videos

  • WAVES AND SOUND

    ERRORLESS |Exercise Progressive Waves|80 Videos

  • VECTORS

    ERRORLESS |Exercise Exercise|223 Videos

  • WORK , ENERGY , POWER AND COLLISION

    ERRORLESS |Exercise Self Evaluation Test|19 Videos

Similar Questions

Explore conceptually related problems

Can beats be observed in two light sources of nearly equal frequencies ?

Intensity of sound at a point is its distance from the source

Two sources of sound are in resonance when

The beats are produced by two sound sources of same amplitude and of nearly equal frequencies. The maximum intensity of beats will be ...... that of one source

Two coherent sources of equal intensity produce maximum intensity of 100 units at a point. If the intensity of one of the sources is reduced by 36% reducing its width, then the intensity of light at the same point will be

Why should two sources of sound have nearly equal frequencies for the formation of beats?

At a place due to beats obtained from two sources of sound

Two coherent sources of intensities I_0 each produce minimum intensity of zero then the maximum intensity they can produce by interference is?

A and B are two point sources of sound (of same frequency) and are kept at a separation. At a point P , the intensity of sound is observed to be I_(0) when only source A is put on. With only B on the intensity is observed to be 2I_(0) . The distance AP is higher than distance BP by half the wavelength of the sound. Find the intensity recorded at P with both sources on. Give your answer for following cases: (a) The sources are coherent and in phase. (b) The sources are coherent and 180° out of phase. (c) The sources are incoherent.

ERRORLESS -WAVES AND SOUND-Interference and Superposition of Waves
  1. Two waves are propagating to the point P along a straight line produce...

    Text Solution

    |

  2. Coherent sources are characterized by the same

    Text Solution

    |

  3. The minimum intensity of sound is zero at a point due to two sources o...

    Text Solution

    |

  4. Two sound waves (expressed in CGS units) given by y(1)=0.3 sin (2 pi)...

    Text Solution

    |

  5. If two waves having amplitudes 2 A and A and same frequency and veloci...

    Text Solution

    |

  6. The intensity ratio of two waves is 1 : 16. The ratio of their amplitu...

    Text Solution

    |

  7. Out of given four waves (1),(2),(3) and (4) y=asin(kx+omegat) .(1) ...

    Text Solution

    |

  8. Two waves of same frequency and intensity superimpose with each other ...

    Text Solution

    |

  9. The superposing waves are represented by the following equations : ...

    Text Solution

    |

  10. The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 co...

    Text Solution

    |

  11. Two waves y(1) =A(1) sin (omega t - beta (1)), y(2)=A(2) sin (omega t...

    Text Solution

    |

  12. If the ratio of amplitude of wave is 2 : 1, then the ratio of maximum ...

    Text Solution

    |

  13. The two interfering waves have intensities in the ratio 9 : 4. The rat...

    Text Solution

    |

  14. If the ratio of amplitude of two waves is 4:3, then the ratio of maxim...

    Text Solution

    |

  15. Equation of motion in the same direction is given by y(1) =A sin (ome...

    Text Solution

    |

  16. The intensity ratio of two waves is 9:1. If they produce interference,...

    Text Solution

    |

  17. The displacements of two intering lightwaves are y(1) = 4 sin omega t ...

    Text Solution

    |

  18. Two waves are represented by y(1)= a sin (omega t + ( pi)/(6)) and y(...

    Text Solution

    |

  19. The amplitude of a wave represented by displacement equation y=(1)/(sq...

    Text Solution

    |

  20. Two waves having equaitons x1=asin(omegat+phi1),x=asin(omegat+phi2) ...

    Text Solution

    |