Find the positive solutions of the system of equations `x^(x+y)=y^n and y^(x+y)= x^(2n). y^n`, where ` ngt0`

Find the particular solution of the differential equation ; (x^2+x y)dy=(x^2+y^2)dx given that y=0\ w h e n\ x=1.

Find a particular solution of the differential equation: (x+y)dy+(x-y)dx=0; y=1\ w h e n\ x=1

Let ' n ' is the number of ordered pair (x ,y) satisfying the system of equations {x^2y^2-2x+y^2=0 2x^2-4x+3+y^2=0(x , y in R) and ' S ' is the sum of all the values of xa n dy satisfying the given system of equations then (a) n > S (b) n < S (c) n-2 = S (d) S/n=2

Let ' n ' is the number of ordered pair (x ,y) satisfying the system of equations {x^2y^2-2x+y^2=0 2x^2-4x+3+y^2=0(x , y in R) and ' S ' is the sum of all the values of xa n dy satisfying the given system of equations then n > S (b) n

(x+y)^(n) + (x-y)^(n) is equal to

(x+y)^(n) + (x-y)^(n) is equal to

The system of equation x+y+z=6, x+4y+6z=20, x+4y+mz=n . Has no solution then

Number of un-order pair solution of (x,y) ofthe equation (1)/(x)+(1)/(y)=(1)/(2007), where x,y in N is

The HCF of x^(2) - y^(2), x^(3) - y^(3), …... x^(n) - y^(n) , where n in N is ………. .

If l + m + n = 0, then the system of equations -2x + y + z = l x - 2y + z = m x + y - 2z = n has