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The length of two open organ pipes are l...

The length of two open organ pipes are `l` and `(l+deltal)` respectively. Neglecting end correction, the frequency of beats between them will b approximately.

A

`v/(2l)`

B

`v/(4l)`

C

`(v Deltal)/(2l^(2))`

D

`(vDelta l)/(l)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The lengths of two organ pipes open at both ends are L and L + d . If they are sounde together, then the beat frequency will be

    A
    `(2Vd)/(L(L+x))`
    B
    `(2Vd)/(L(L+d))`
    C
    `(2L(L+d))/(Vd)`
    D
    `(Vd)/(2L(L+d))`

  • Two closed organ pipes have lengths L and L+X . When two pipes are sounded together , the beat frequency is

    A
    `(vx)/(4L(L+x))`
    B
    `(vx)/(4L(L-x))`
    C
    `(4L(L+x))/(vx)`
    D
    `(2L(L-x))/(vx)`

  • The length of a given open end and closed end pipes are l_0 " and " l_c respectively. If both the pipes emit same fundamental notes, then the ratio l_0//l_c is

    A
    `sqrt2:1`
    B
    `2:1`
    C
    `1:2`
    D
    `1:sqrt2`

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