If `A=[(1,tan theta),(-tan theta,1)]` ,show that `A^(prime)A^(- 1)=[(cos2theta,-sin2theta),(sin2theta,cos2theta)]`

If A = [(1,-tan""(theta)/(2)),(tan""(theta)/(2), 1)] and B = [(1,tan""(theta)/(2)),(-tan""(theta)/(2), 1)] show that, AB^(-1) = [(costheta,-sin theta),(sin theta, cos theta)] .

If A=[[1,tan theta-tan theta,1]], show that A'A^(-1)=[[cos2 theta,-sin2 thetasin2 theta,cos2 theta]]

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta) =

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

Show that [[1 , -tan theta ],[ tan theta, 1]][[1, tan theta],[ -tan theta, 1]]^(-1)=[[cos 2 theta, -sin 2 theta],[ sin 2 theta, cos 2 theta]]

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

Prove : (1+sin2theta-cos2theta)/(1+sin2theta+cos2theta)=tantheta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta