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According to the equation N(2)O(3)(g) ...

According to the equation
`N_(2)O_(3)(g) + 6H_(2)(g) rArr 2NH_(3)(g) + 3H_(2)O(g)`
how many moles of `NH_(3)(g)` could be formed from the reaction of 0.22 mol of `N_(2)O_(3)`(g) with 0.87 mol of `H_(2)(g)`?

A

0.29mol

B

0.44mol

C

0.73mol

D

1.1mol

Text Solution

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The correct Answer is:
A
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