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For the sequential reactions: 2A overs...

For the sequential reactions:
`2A overset(80%)to 3B + C`
`2B overset(50%)to 5D + E`
Moles of A needed for the formation of 1.5 moles of D is:

A

0.6

B

0.4

C

1

D

1.16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many moles of A are needed for the formation of 1.5 moles of D through the given sequential reactions, we can break it down step by step. ### Step 1: Understand the first reaction The first reaction is: \[ 2A \overset{80\%}{\rightarrow} 3B + C \] From this reaction, we can see that 2 moles of A produce 3 moles of B with an 80% yield. ### Step 2: Calculate the effective moles of B produced from A To find out how many moles of A are needed to produce a certain amount of B, we first need to determine how many moles of B we can produce from 2 moles of A at 80% yield. The theoretical yield of B from 2 moles of A is 3 moles. However, due to the 80% yield: \[ \text{Effective moles of B} = \text{Theoretical moles of B} \times \text{Yield} \] \[ = 3 \times \frac{80}{100} = 2.4 \text{ moles of B} \] ### Step 3: Understand the second reaction The second reaction is: \[ 2B \overset{50\%}{\rightarrow} 5D + E \] From this reaction, 2 moles of B produce 5 moles of D with a 50% yield. ### Step 4: Calculate the effective moles of D produced from B Now, we need to find out how many moles of D can be produced from the effective moles of B (2.4 moles): \[ \text{Theoretical moles of D} = \text{Effective moles of B} \times \frac{5}{2} \] \[ = 2.4 \times \frac{5}{2} = 6 \text{ moles of D} \] Now, considering the 50% yield: \[ \text{Effective moles of D} = 6 \times \frac{50}{100} = 3 \text{ moles of D} \] ### Step 5: Determine how many moles of A are needed for 1.5 moles of D Now we need to find out how many moles of A are required to produce 1.5 moles of D. Since we can produce 3 moles of D from 2.4 moles of B, we can set up a ratio: If 3 moles of D are produced from 2.4 moles of B, then: \[ \text{Moles of B needed for 1.5 moles of D} = \frac{1.5}{3} \times 2.4 = 1.2 \text{ moles of B} \] ### Step 6: Calculate moles of A needed for 1.2 moles of B Now we need to find out how many moles of A are needed to produce 1.2 moles of B. From the first reaction, we know that: \[ 2 \text{ moles of A} \rightarrow 2.4 \text{ moles of B} \] Using a ratio: If 2 moles of A produce 2.4 moles of B, then: \[ \text{Moles of A needed for 1.2 moles of B} = \frac{1.2}{2.4} \times 2 = 1 \text{ mole of A} \] ### Final Answer Thus, the moles of A needed for the formation of 1.5 moles of D is: \[ \boxed{1} \]
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