Home
Class 11
CHEMISTRY
A certain organic substance used as a so...

A certain organic substance used as a solvent in many reactions contains carbon, hydrogen, oxygen and sulphur. Weight % of hydrogen in the compound is 7.7. The weight ratio `C : O : S = 3:2:4`. What is the least possible molar mas of the compound?

A

86

B

63

C

94

D

78

Text Solution

AI Generated Solution

The correct Answer is:
To find the least possible molar mass of the organic compound containing carbon (C), hydrogen (H), oxygen (O), and sulfur (S), we will follow these steps: ### Step 1: Determine the mass percentages of C, O, and S Given that the weight percentage of hydrogen (H) in the compound is 7.7%, we can find the remaining mass percentage for carbon, oxygen, and sulfur. - Total mass = 100 g - Mass of H = 7.7 g - Remaining mass = 100 g - 7.7 g = 92.3 g The weight ratio of C:O:S is given as 3:2:4. The total parts in this ratio = 3 + 2 + 4 = 9 parts. ### Step 2: Calculate the mass percentages of C, O, and S Using the ratio, we can find the mass percentages of C, O, and S: - Mass of C = (3/9) * 92.3 g = 30.73 g - Mass of O = (2/9) * 92.3 g = 20.52 g - Mass of S = (4/9) * 92.3 g = 41.04 g ### Step 3: Create a table of mass percentages and atomic masses Now, we will summarize the information in a table: | Element | Mass % | Atomic Mass (g/mol) | Moles | |---------|--------|---------------------|-------| | C | 30.73 | 12 | 30.73/12 = 2.56 | | H | 7.7 | 1 | 7.7/1 = 7.7 | | O | 20.52 | 16 | 20.52/16 = 1.28 | | S | 41.04 | 32 | 41.04/32 = 1.28 | ### Step 4: Calculate the simplest ratio of moles Next, we will divide each mole value by the smallest number of moles calculated: - C: 2.56 / 1.28 = 2 - H: 7.7 / 1.28 = 6 - O: 1.28 / 1.28 = 1 - S: 1.28 / 1.28 = 1 ### Step 5: Write the empirical formula From the simplest ratios, we can write the empirical formula as: \[ \text{C}_2\text{H}_6\text{O}_1\text{S}_1 \] ### Step 6: Calculate the molar mass of the empirical formula Now, we will calculate the molar mass of the empirical formula: - Molar mass = (2 × 12) + (6 × 1) + (1 × 16) + (1 × 32) - Molar mass = 24 + 6 + 16 + 32 = 78 g/mol ### Conclusion The least possible molar mass of the compound is **78 g/mol**. ---
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS

    GRB PUBLICATION|Exercise POAC Based Questions|16 Videos
  • MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS

    GRB PUBLICATION|Exercise Experimental Methods|24 Videos
  • MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS

    GRB PUBLICATION|Exercise Sequential and Parallel Reactions|17 Videos
  • ISOMERISM

    GRB PUBLICATION|Exercise SUBJECTIVE TYPE|67 Videos
  • NOMENCLATURE AND CLASSIFICATION

    GRB PUBLICATION|Exercise Subjective Type|24 Videos

Similar Questions

Explore conceptually related problems

A compound contains 34.8% Oxygen, 52.2% carbon and 13.0% Hydrogen. What is the empirical formula of the compound ?

An organic compound contains 49.3 % carbon,6.84 % hydrogen and its vapour density is 73 Molecular formula of the compound is

If 75.2% of compound is carbon and the rest of the weight is hydrogen, the formula of the compound is

An organic compound having carbon, hydrogen andsulphus contsains 4% of sulphur. The minimum molecular weight of the compound is

An organic compound contains carbon ,hydrogen and oxengen .The percentage of carbon is 36 while of hydrogen is 4.The percentage of oxygen will be

GRB PUBLICATION-MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS-Empirical and molecular formula
  1. The simplest formula of a compound containing 50% of an element X (ato...

    Text Solution

    |

  2. The oxides of a certain (hypothetical) element contain 27.28%, 42.86% ...

    Text Solution

    |

  3. A certain organic substance used as a solvent in many reactions contai...

    Text Solution

    |

  4. In an organic compound of molar mass 108 gm mol^-1 C, H and N atoms ar...

    Text Solution

    |

  5. 64g of an organic compound contains 24 g of carbon, 8gm of hydrogen ...

    Text Solution

    |

  6. X and Y are two elements which form X(2)Y(3 and X(3)Y(4). If 0.20 mol ...

    Text Solution

    |

  7. A compound has the molecular formula X(4)O(6). If 10 g "of" X(4)O(6) h...

    Text Solution

    |

  8. An unidentified bivalent metal M reacts with unidentified halogen X to...

    Text Solution

    |

  9. A 0.239g sample of a gas in a 100-ml flask exerts a pressure of 600mm ...

    Text Solution

    |

  10. A certain oxide of iron contains 2.5 grams of oxide for every 7.0grams...

    Text Solution

    |

  11. Disilane, Si(2)H(X) is analysed and found to contain 90.32% silicon by...

    Text Solution

    |

  12. A gaseous hydrocarbon gives upon combustion, 0.72 g of water and 3.08 ...

    Text Solution

    |

  13. Each 9.4gm of a compound contains 7.2gm carbon, 0.6gm hydrogen and res...

    Text Solution

    |

  14. Three different oxides of nitrogen each contain 7.00 g of hydrogen and...

    Text Solution

    |

  15. A compound contains 69.5% oxygen and 30.5% nitrogen and its molecualr ...

    Text Solution

    |

  16. 26.8g of Na(2)SO(4). nH(2)O contains 12.6 g of water. The value of n i...

    Text Solution

    |

  17. Which of the following series of compounds have same mass percentage o...

    Text Solution

    |

  18. 60 gm of an organic compound containing C,H and O atoms on complete co...

    Text Solution

    |

  19. Aspartame an artificial sweetner contains 9.52% by weight of nitrogen....

    Text Solution

    |

  20. A compound contains 38.8% C, 16.0% H and 45.2% N. The empirical formul...

    Text Solution

    |