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The percent composition of the high expl...

The percent composition of the high explosive HNS is:`{: (C,H,N,O),(37.35%, 1.34%, 18.67%, 42.65%):}`
The molar mass of HNS is 450.22. What is the molecular formular of HNS?

A

`C_(13)H_(4)N_(7)O_(12)`

B

`C_(14)H_(6)N_(6)O_(12)`

C

`C_(15)H_(10)N_(6)O_(11)`

D

`C_(16)H_(12)N_(5)O_(11)`

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The correct Answer is:
To determine the molecular formula of HNS from its percent composition and molar mass, we can follow these steps: ### Step 1: Convert Percent Composition to Mass Assuming we have 100 g of the compound, the mass of each element can be calculated directly from the percent composition: - Carbon (C): 37.35 g - Hydrogen (H): 1.34 g - Nitrogen (N): 18.67 g - Oxygen (O): 42.65 g ### Step 2: Convert Mass to Moles Next, we convert the mass of each element to moles using their respective molar masses: - Molar mass of Carbon (C) = 12 g/mol - Molar mass of Hydrogen (H) = 1 g/mol - Molar mass of Nitrogen (N) = 14 g/mol - Molar mass of Oxygen (O) = 16 g/mol Calculating the moles for each element: - Moles of C = 37.35 g / 12 g/mol = 3.1125 moles - Moles of H = 1.34 g / 1 g/mol = 1.34 moles - Moles of N = 18.67 g / 14 g/mol = 1.3343 moles - Moles of O = 42.65 g / 16 g/mol = 2.6641 moles ### Step 3: Find the Simplest Mole Ratio Now, we divide each of the mole values by the smallest number of moles calculated: - C: 3.1125 / 1.3343 ≈ 2.33 - H: 1.34 / 1.3343 ≈ 1 - N: 1.3343 / 1.3343 = 1 - O: 2.6641 / 1.3343 ≈ 2 ### Step 4: Convert to Whole Numbers To convert the ratios into whole numbers, we can multiply each by a common factor. In this case, multiplying by 3 gives: - C: 2.33 * 3 ≈ 7 - H: 1 * 3 = 3 - N: 1 * 3 = 3 - O: 2 * 3 = 6 Thus, the empirical formula is approximately C7H3N3O6. ### Step 5: Determine the Molecular Formula Next, we need to find the molar mass of the empirical formula: - Molar mass of C7H3N3O6 = (7*12) + (3*1) + (3*14) + (6*16) = 84 + 3 + 42 + 96 = 225 g/mol Now, we can find the ratio of the molar mass of the compound to the empirical formula mass: - Ratio = Molar mass of HNS / Molar mass of empirical formula = 450.22 g/mol / 225 g/mol ≈ 2 ### Step 6: Calculate the Molecular Formula Finally, we multiply the subscripts in the empirical formula by this ratio: - C: 7 * 2 = 14 - H: 3 * 2 = 6 - N: 3 * 2 = 6 - O: 6 * 2 = 12 Thus, the molecular formula of HNS is C14H6N6O12. ### Final Answer The molecular formula of HNS is **C14H6N6O12**.
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