500 mL of 0.1 M KCl, 200 ml of 0.01 M `NaNO_(3)` and 500 ml of 0.1 M `AgNO_(3)` was mixed. The molarity of `K^(+)`,`Ag^(+)`, `Cl^(-)`, `Na^(+)`, `NO^(3-)` in the solution would be:

Options

A. `[K^(+)] = 0.04, [Ag^(+)]= 0.04, {Na^(+)]=0.002 [Cl^(-)] = 0.04 , [NO_(3^(-)] = 0.042`
B. `[K^(+)]=0.04, [Na^(+)] = 0.00166, [NO^(-_(3)]]= 0.0433`
C. `[K^(+)]= 0.04, [Ag^(+)] = 0.05, [Na^(+)] = 0.0025, [Cl^(-)] = 0.05, [NO^(-_(3)] = 0.0525]`
D. `[K^(+)] = 0.05, [Na^(+)]= 0.0025 [Cl^(-)]= 0.05, [NO^(-_(3)] = 0.0525`

Answer

B