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similar to % labelling of oleum ,a mixt...

similar to % labelling of oleum ,a mixture of `H_(3)PO_(3)` and `P_(4)O_(6)` is labelled as (100 +x)% where x is maximum mass of water which can reacts with `P_(4)O_(6)` present in 100 gm mixture of `H_(3)PO_(3)` and `P_(4)O_(6)`
`P_(4)O_(6) + H_(3)`

A

1.25 atm

B

2.23 atm

C

0.25 atm

D

None of the above

Text Solution

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The correct Answer is:
A
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Two substances P_(4) & O_(2) are allowed to react completely to form mixture of P_(4)O_(6) & P_(4)O_(10) leaving none of the reactants .Using this information calculate the moles of P_(4)O_(6) and P_(4)H_(10) in the final mixture when the following amounts of P_(4) & O_(2) are taken. P_(4) + 3O_(2) to P_(4)O_(6) P_(4) + 5O_(2) to P_(4)O_(10) (i) If 1 mole P_(4) & 4 mole of O_(2) (ii) If 3 mole P_(4) & 11 mole of O_(2) (iii) If 3 mole P_(4) & 13 mole of O_(2)

H_(4)underline(P_(2))O_()+H_(2)O to H_(3)PO_(3)

Knowledge Check

  • P_(4)O_(6) reacts with water to give

    A
    `H_(3)PO_(3)`
    B
    `H_(4)P_(2)O_(7)`
    C
    `HPO_(3)`
    D
    `H_(3)PO_(4)`
  • underline(P_(4))O_(6)+6H _(2)O to 4H_(3)PO_(3)

    A
    If product is oxy acid with -ic suffix.
    B
    If product is oxy acid with -ous suffix
    C
    If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
    D
    If product is not oxy acid, neither with -ic suffix nor with -ous suffix
  • P_(4)+NaOH+H_(2)O rarr NaH_(2)PO_(3)+PH_(3) is

    A
    oxidation reaction
    B
    reduction reaction
    C
    both oxidation abnd reduction reaction
    D
    none fo these
  • Similar Questions

    Explore conceptually related problems

    H_(4)underline(P_(2))O_()+H_(2)O to H_(3)PO_(3)

    H_(3)underline(P)O_(5)+H_(2)O to H_(3)PO_(4)+H_(2)O_(2)

    H_(4)underline(P_(2))O_(6)+H_(2)O to H_(3)PO_(3)+H_(3)PO_(4)

    H_(4)underline(P_(2))O_(6)+H_(2)O to H_(3)PO_(3)+H_(3)PO_(4)

    underline(P_(4))O_(10)+H_(2)O to H_(3)PO_(4)