If, from 10 moles `NH_(3)` and 5 moles of `H_(2)SO_(4),` all the H-atoms are removed in order to form `H_(2)` gas, then find the number moles of `H_(2)` formed.

Answer

To solve the problem of how many moles of \( H_2 \) gas are formed from the given moles of \( NH_3 \) and \( H_2SO_4 \), we will follow these steps:

### Step 1: Determine the number of hydrogen atoms in \( NH_3 \)
- Each molecule of ammonia (\( NH_3 \)) contains 3 hydrogen atoms.
- Given that there are 10 moles of \( NH_3 \):
\[ \text{Total H from } NH_3 = 10 \text{ moles} \times 3 \text{ H/molecule} = 30 \text{ moles of H} \]

### Step 2: Determine the number of hydrogen atoms in \( H_2SO_4 \)
- Each molecule of sulfuric acid (\( H_2SO_4 \)) contains 2 hydrogen atoms.
- Given that there are 5 moles of \( H_2SO_4 \):
\[ \text{Total H from } H_2SO_4 = 5 \text{ moles} \times 2 \text{ H/molecule} = 10 \text{ moles of H} \]

### Step 3: Calculate the total number of hydrogen atoms
- Now, we add the hydrogen atoms from both sources:
\[ \text{Total H} = 30 \text{ moles from } NH_3 + 10 \text{ moles from } H_2SO_4 = 40 \text{ moles of H} \]

### Step 4: Determine the number of moles of \( H_2 \) produced
- To form \( H_2 \) gas, 2 hydrogen atoms combine to form 1 molecule of \( H_2 \).
- Therefore, the number of moles of \( H_2 \) produced from 40 moles of hydrogen atoms is:
\[ \text{Moles of } H_2 = \frac{40 \text{ moles of H}}{2 \text{ H/molecule}} = 20 \text{ moles of } H_2 \]

### Final Answer
Thus, the number of moles of \( H_2 \) formed is **20 moles**.

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