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5 g of K(2)SO(4) was dissolved in 250 ml...

5 g of `K_(2)SO_(4)` was dissolved in 250 ml of solution. How many ml of this solution sholuld be used so that 2.33 g of `BaSO_(4)` may be precipitated from `BaCl_(2)` solution.
`K_(2)SO_(4)+BaCl_(2)rarrBaSO_(4)+2KCl`

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5g of K_(2)SO_(4) are dissolved in 250mL of solution. How many mL of this solution should be used so that 1.2 of BaSO_(4) may be precipated from BaCl_(2) solution?

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