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The 'roasting' of 100.0 g of a copper or...

The 'roasting' of 100.0 g of a copper ore yielded 71.8 g pure copper. If the ore is composed of `Cu_(2)S` and `CuS` with `4.5%` inert impurity, calculate the percent of `Cu_(2)S` in the ore.
The reactions are:
`Cu_(2)S+O_(2)rarr2Cu+SO_(2)` and
`CuS+O_(2)rarrCu+SO_(2)`
[Atomic masses Cu=63.5m S=32]
[Give answer exculuding decimal places]

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